Extract first /part/ of url with Regex

Question

How to make regex which will extract this first part of url /adjusterAnalytics/?

Extract without slash.

http://192.168.15.122:3000/adjusterAnalytics/individual/Xh7HTIgGw1RqnsK2TuJtiUIMahy2

Any advice is welcome.

You can refer this [URL API MDN](https://developer.mozilla.org/en-US/docs/Web/API/URL) — Code Maniac, Apr 18 '19 at 14:53
Possible duplicate of [How do I parse a URL into hostname and path in javascript?](https://stackoverflow.com/questions/736513/how-do-i-parse-a-url-into-hostname-and-path-in-javascript) — Kunal Mukherjee, Apr 18 '19 at 14:54
Of course you can do this with regex. But there are way better tools available to do this. — Mark Baijens, Apr 18 '19 at 14:56

online Thomas · Answer 1 · 2019-04-18T15:08:30.790

I overcomplicated it probably, but I made this regex for you

(?<schema>[a-z]+):\/\/(?<domain>[^:/]+)(?<port>:[0-9]+)\/(?<theFirstPart>[\w]+)\/.*

Usage within js:

const regex = /(?<schema>[a-z]+):\/\/(?<domain>[^:/]+)(?<port>:[0-9]+)\/(?<theFirstPart>[\w]+)\/.*/gm;
const str = `http://192.168.15.122:3000/adjusterAnalytics/individual/Xh7HTIgGw1RqnsK2TuJtiUIMahy2`;
let m;

while ((m = regex.exec(str)) !== null) {
// This is necessary to avoid infinite loops with zero-width matches
if (m.index === regex.lastIndex) {
    regex.lastIndex++;
}

// The result can be accessed through the `m`-variable.
m.forEach((match, groupIndex) => {
    console.log(`Found match, group ${groupIndex}: ${match}`);
});
}

https://regex101.com/r/IU2Ms0/2

score 1 · Accepted Answer · answered Apr 18 '19 at 15:06

There is way to extract the required part by using negative look-behind and a lazy quantifier:

const [,match] = "http://192.168.15.122:3000/adjusterAnalytics/individual/Xh7HTIgGw1RqnsK2TuJtiUIMahy2".match(/(?<![\/:])\/(.*?)\//);

console.log(match)

Extract first /part/ of url with Regex

2 Answers2