Is there any guarantees that a stays a valid object when I do a = std::move(a)? Should I correctly handle this case when implement move operator=? If so, are there any best practices to do it?
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You should handle that case. It is sometimes not possible to predict if what you are moving is the object itself – Aykhan Hagverdili Apr 18 '19 at 21:13
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You can do an explicit `if (this != &other)`, but this may not be the best implementation considering `a = std::move(a)` does not happen too often – Aykhan Hagverdili Apr 18 '19 at 21:14
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@Ayxan That should probably be in an answer – Justin Apr 18 '19 at 21:16