Can any one tell me how to open another app using flutter?

Question

I want to open a bunch of music app links using links data I have in firebase. I want to open, amazonPrimeMusic, Ganna, Spotify, Wynk, JioSavaan to name some.

Widget buildResultCard(data) {
  List items = [Text(data['Ganna']),
    IconButton(icon:Icon(Icons.all_inclusive),
      onPressed: ()=> {Text("Ganna")}
    ),

    Text(data['Wynk']),
    IconButton(icon:Icon(Icons.all_inclusive),
      onPressed: ()=> {Text("Ganna")}
    ),

    Text(data['JioSavaan']),
    IconButton(icon:Icon(Icons.all_inclusive),
      onPressed: ()=> {Text("Ganna")}
    ),

    Text(data['PrimeMusic']),
    IconButton(icon:Icon(Icons.all_inclusive),
      onPressed: ()=> {Text("Ganna")}
    )
  ];

  return ListView.builder(
    padding: EdgeInsets.only(top: 20),
    itemCount: items.length,
    itemBuilder: (BuildContext context, int index) {
      return items[index];
    },
  );
}

when I tap the button in the list it should open up the particular app for which the link is, for example for AmazonPrimeMusic link, it should open the Amazon music app.

Answer 1

add this to the pubspec.yaml file under dependencies-

  device_apps:
  android_intent:
  url_launcher:

and add these to the top -

import 'package:device_apps/device_apps.dart';
import 'package:url_launcher/url_launcher.dart';
import 'package:android_intent/android_intent.dart';

and here is the sample code -

_openJioSavaan (data) async
{String dt = data['JioSavaan'] as String;
  bool isInstalled = await DeviceApps.isAppInstalled('com.jio.media.jiobeats');
if (isInstalled != false)
 {
    AndroidIntent intent = AndroidIntent(
      action: 'action_view',
      data: dt
  );
  await intent.launch();
 }
else
  {
  String url = dt;
  if (await canLaunch(url)) 
    await launch(url);
   else 
    throw 'Could not launch $url';
}
}

Answer 2

You can use flutter_appavailability package. This plugin allows you to check if an app is installed in mobile and using this plugin you can launch an app.

If already installed then launch otherwise open link in WebView using url_launcher.

Answer 3

Hello you actually need two packages. Check the versions before you use them. First of all you need the id of the app. For example for facebook lite the id is com.facebook.lite. You acn find the id if you go to playstore click share and cope the link. The link for facebook lite is https://play.google.com/store/apps/details?id=com.facebook.lite from this one you can easily understand that the id is after "id=". Its the same on the other apps too.

device_apps: ^2.1.1 url_launcher: ^6.0.3

try {
  ///checks if the app is installed on your mobile device
  bool isInstalled = await DeviceApps.isAppInstalled('si.modula.android.instantheartrate');
  if (isInstalled) {
     DeviceApps.openApp("si.modula.android.instantheartrate");
   } else {
     ///if the app is not installed it lunches google play store so you can install it from there
   launch("market://details?id=" +"si.modula.android.instantheartrate");
   }
} catch (e) {
    print(e);
}

so the code above check if you have already installed the application. If you have done it it will lunch the application if not it is going to open google playstore so you can see it there. It works only for android devices.

Answer 4

Updated : url_launcher: ^6.1.4

          void launchAnotherApp() async {
            if (!await launchUrl(Uri.parse("https://www.instagram.com/username/"),
                mode: LaunchMode.externalApplication)) {
              throw 'Could not launch ';
            }
          }

It opens another app on your phone. If targeted app not installed on your device it will open in webview.

Answer 5

I think you can use external_app_launcher: ^3.0.0

https://pub.dev/packages/external_app_launcher

Answer 6

You can easily do it with the help of external_app_launcher.

A Flutter plugin that helps you to open another app from your app. The package asks you for four parameters out of which two are mandatory.

Example code:

RaisedButton(
  color: Colors.blue,
  onPressed: ()  {
    LaunchApp.openApp(
      androidPackageName: 'net.pulsesecure.pulsesecure',
      iosUrlScheme: 'pulsesecure://',
      appStoreLink: 'itms-apps://itunes.apple.com/us/app/pulse-secure/id945832041',
    );
    // Enter the package name of the App you want to open and for iOS add the URLscheme to the Info.plist file.
    // The `openStore` argument decides whether the app redirects to PlayStore or AppStore.
    // For testing purpose you can enter com.instagram.android
  },
  child: Container(
    child: Center(
      child: Text("Open",
        textAlign: TextAlign.center,
      ),
    ),
  ),
)

Answer 7

All you need to do is just install the URL launcher and external app launcher in case your user doesn't have an app installed. So he can be redirected to the play store link.

import 'package:external_app_launcher/external_app_launcher.dart';
import 'package:url_launcher/url_launcher_string.dart';

onTap: () async {
            var teamsAppUrl = 'msteams:';
            try {
              await launchUrlString(teamsAppUrl); // Attempt to launch the Teams app
            } catch (e) {
              var openAppResult = await LaunchApp.openApp(
                androidPackageName: 'com.microsoft.teams',
                iosUrlScheme: 'msteams:',
              );/
            }
},