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I'm trying to convert that data type to string. Even that's not working. Example: str(0123) But this is possible a="0123". My complete assumption is 0123 is not accepted because it is octal not an integer. So, octal are not allowed in python. Please correct me if i'm wrong.

Tharun Audhimoolam
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    Octal is `0o123`, but `0123` was allowed in Python2 for octal. But this is forbidden in Python3. – Daniel Apr 20 '19 at 11:48

1 Answers1

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You're looking for 0o123. Numbers that start with only a zero, which is not the only symbol in the token, are invalid syntax.

ForceBru
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  • @JohnColeman, that question has the Python-2.7 tag, so I'm not sure how this one is a dupe of that in the first place (although its [original version](https://stackoverflow.com/revisions/26749728/1) is tagged Python 3.x _as well as_ Python 2.7, while using Python 2.7's syntax for `print`). So, my answer about Python 3.x probably wouldn't fit the question about Python 2.7 – ForceBru Apr 20 '19 at 11:56
  • Yes it was a bad duplicate target, sorry. I changed it now. – ayhan Apr 20 '19 at 12:03
  • @ayhan, the OP of that post already knew that "the 0 for octal does not work any more in python (i.e. does not work in _python3_)", and their question was why Python didn't change the meaning of tokens like `001234`, that _don't_ start with `0o` in Python 3. [This question](https://stackoverflow.com/questions/11620151/what-do-numbers-starting-with-0-mean-in-python) may be a better dupe target. It's still tagged Python 2.7, tough, and it's not really about the difference between Py 2.7 and Py 3. – ForceBru Apr 20 '19 at 12:12