java.lang.NumberFormatException: For input string: "XYZ_-1556021952300"

Question

I have a string of chars and integers which I am splitting to take out the negative integer value and then check if the value is negative, then do something inside if block. Code sample is as below:

java.util.Iterator<WebElement> i = elements.iterator();
while (i.hasNext()) {
    WebElement element = i.next();
    String str = element.getAttribute("name");
    System.out.println(str);
    String[] arrOfStr = str.split("_");
    System.out.println(arrOfStr);
    long res = Integer.parseInt(arrOfStr[1]);
    System.out.println(res);

    if (res < 0) {
        System.out.println("Inside if");
        System.out.println(data);
        Thread.sleep(10000);
        Select selectBox = new Select(element);
        selectBox.selectByVisibleText(data);
    }

why are you parsing an integer using Integer.parseInt() into a long? — vc73, Apr 23 '19 at 12:38
The number you are trying to parse is too big (small) to fit into an Integer. Try Long.parseLong — jalynn2, Apr 23 '19 at 12:41
What about `arrOfStr[1].charAt(0) == '-'` as the condition for your `if` instead of `res < 0`? — Joakim Danielson, Apr 23 '19 at 12:41
try `long res = Long.parseLong(arrOfStr[1]);` instead of `Integer.parseInt(arrOfStr[1])` — soorapadman, Apr 23 '19 at 12:43
Give an example of data which “arrOfStr[1]” will hold ... — Zain Arshad, Apr 23 '19 at 12:43

score 0 · Answer 1 · answered Apr 23 '19 at 13:19

You are trying to parse in Integer for input string: “XYZ_-1556021952300”. Since there is character which cannot be parse into number. So you are getting this exception.

May be because of the following code you are facing this issue.

long res = Integer.parseInt(arr0fStr[1]);

Change this line to something like this:

String res = arrOfStr[1];

java.lang.NumberFormatException: For input string: "XYZ_-1556021952300"

1 Answers1