How to exit from bash script if it started with timeout?

Question

I run my scripts with timeout function

timeout 86400 ./start.sh

How can I terminate script before timeout counted down? Ctr+C does not work in this case Closing terminal still leaves process on background

This is my full script:

python3 startmeVtest.py 5 2 10
timeout 86400 ./start.sh
sleep 4
python3 startmeVtest.py 10 4 20
timeout 86400 ./start.sh
sleep 4
python3 startmeVtest.py 20 4 40
timeout 86400 ./start.sh
sleep 4
python3 startmeVtest.py 30 8 50
timeout 86400 ./start.sh
sleep 4
python3 startmeVtest.py 50 9 70
./start.sh
exit 0

I would like to exit from my bash script before it finish without using ps -A all the time.

Possible duplicate of [How to set the process name of a shell script?](https://stackoverflow.com/questions/3075682/how-to-set-the-process-name-of-a-shell-script) — Lajos Arpad, Apr 24 '19 at 11:26

score 0 · Answer 1 · answered Apr 24 '19 at 11:30

0

find a list of processes by name using grep

pgrep timeout

kill all processes by name

pkill timeout

answered Apr 24 '19 at 11:30

宏杰李

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score 0 · Answer 2 · answered Apr 24 '19 at 11:44

0

The below will kill your start.sh script directly

pkill -f "start.sh"

answered Apr 24 '19 at 11:44

nullPointer

4,419
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1

This has the extra educational benefit of killing all scripts on the system named `start.sh` which will teach others not to use generic names. – stark Apr 24 '19 at 16:59
That's true! :) – nullPointer Apr 25 '19 at 06:40

How to exit from bash script if it started with timeout?

2 Answers2