Why [] is [] gives False in Python

Question

I'm bit confused with this logic. When the following gives True in python

print('' is '')  #True
print('' == '')  #True
print([] ==  []) #True
print({} ==  {}) #True

But why these statement gives False?

print([] is  []) #False
print({} is  {}) #False

Similar question to https://stackoverflow.com/questions/42553259/why-does-is-evaluate-to-false-in-python — Jaye Hernandez, Apr 25 '19 at 06:07

score 6 · Accepted Answer · answered Apr 25 '19 at 06:07

6

The == operator compares the values of both the operands and checks for value equality. Whereas is operator checks whether both the operands refer to the same object or not.

https://www.geeksforgeeks.org/difference-operator-python/

answered Apr 25 '19 at 06:07

James Holmes

394
2
5

Then why `'' is ''` gives `True` if it comparing the objects? – Vanjith Apr 25 '19 at 06:14
1

@Vanjith: Because both `''` expressions happened to evaluate to the same object. This is permitted but not required for immutable objects. – user2357112 Apr 25 '19 at 06:26

Why [] is [] gives False in Python

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