destructuring base on dynamic value es6

Question

I have an express endpoint, I need to get the query pass from the frontend

const { filterType1, filterType2 } = req.query

the problem is the filterType is from elsewhere, says it's list of array

const list = ['priceFilter', 'ageFilter', 'destinationFilter']

can I do this?

const { list.map(o => o) } = req.query which means

const { priceFilter , ageFilter, destinationFilter } = req.query

No, it's impossible, because that would require dynamic variable names. — CertainPerformance, Apr 26 '19 at 02:40
Probably a duplicate (but I won't close yours for now): https://stackoverflow.com/q/35939289/5768908 — Gerardo Furtado, Apr 26 '19 at 02:48
@CertainPerformance if it's not possible how should I solve above problem? you have a list that's coming from elsewhere, you want to pass in in req.query.somethingdynamic here. Do I have to hard code it, next time the list got updated I have to manually modify the query param? — Hanz, Apr 26 '19 at 03:32
Simple, just don't destructure - instead, just iterate through the `list` array (or the `Object.entries` of the `req.query`) — CertainPerformance, Apr 26 '19 at 03:51
@Hanz: The problem is already solved. Just don't destructure — slebetman, Apr 26 '19 at 04:40

score 0 · Answer 1 · answered Apr 26 '19 at 03:37

You can filter request's query parameters according to the filterTypes array and then access the filters by iterating.

function getFilters(req, filterTypes) {
  return Object.keys(req.query).reduce((acc, k) => {
    const isAllowedFilter = filterTypes.some(type => type === k);
    if (isAllowedFilter) {
      return { ...acc, [k]: req.query[k] };
    }
    return acc;
  }, {});
}

const filterTypes = ['priceFilter', 'ageFilter', 'destinationFilter'];

const req = {
  query: {
    priceFilter: '50-100',
    ageFilter: '8-20',
    destinationFilter: 'foo',
    unknownFilter: 'unknown',
  },
};

const filters = getFilters(req, filterTypes);

Object.keys(filters).forEach(k => console.log(`${k} -> ${filters[k]}`));

I don't want to get the filters, I want to pass it. – Hanz Apr 26 '19 at 06:27 — Hanz, Apr 26 '19 at 06:27

destructuring base on dynamic value es6

1 Answers1