How to print the latest commit ID from the git repo using shell script

Question

I have the following shell script in linux environment, in which arr has the list of git repo paths and when I tried running this script, I am getting into that path through the line 3, but I am not able to get the latest commit ID and save in the variable, what I am missing in this code and how to get that commit ID in that variable "commit_ID".

for i in "${arr[@]}"
do
 cd $i
 echo $i
 commit_ID = git log -1
 echo $commit_ID
done

Try changing commit_ID line to `commit_ID=git log -n1`. Put backticks before git and after 1. See if that works. You might also want to do a `cd ..` before `done` to return to the parent directory. — zedfoxus, Apr 26 '19 at 04:07
Rather `commit_ID=$( git log -n1 )`, no white spaces around the =. — eftshift0, Apr 26 '19 at 04:14
It is just printing a blank line, when I tried commit_ID = ``git log -n1`` — venkatraman Balasubramanian, Apr 26 '19 at 04:16
And about the cd, I guess it should be `cd -`, so that it went out to whatever path it was before (the parameter might be comprised of 2 directories... or an absolute path or what not). — eftshift0, Apr 26 '19 at 04:18
Don't use `cd`. Try `commit_ID=$(git --git-dir=$i/.git log -n1)` instead. If `$i` is a bare repo, don't append `/.git`. — ElpieKay, Apr 26 '19 at 04:22
Thanks @eftshift0, it worked when I tried like commit_ID=$( git log -n1 ) , thanks others for your suggestions. — venkatraman Balasubramanian, Apr 26 '19 at 04:25

score 11 · Answer 1 · answered Apr 26 '19 at 05:00

11

Instead of git log -n1, you could instead use:

COMMIT_ID=$(git rev-parse --verify HEAD)

answered Apr 26 '19 at 05:00

VonC

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How to print the latest commit ID from the git repo using shell script

1 Answers1