I want to capture the third comma in strings like:
98,52,"110,18479456000019"
I thought of something like a character except:
[^"0123456789]
But, result was the capture of all commas.
After that, I've tried some regex about nth capture - seems to be a solution -, but none works.
How do I solve this problem?
There are several ways to capture the third ,. This RegEx is one way to do so:
([\d,])\x22\d+(,)\d+\x22
where your desired , is in the second group (,), just to be simple, and you can call it using $2.
I have added additional boundaries to this RegEx for safety, which you can remove it:
\x22 is just ", which you can replace, if you wish:
([\d,])"\d+(,)\d+"
You can also use (\) and escape a char, where necessary.
If your input would be a bit more complex, maybe such as this:
you might create a middle boundary before the third , and add all possible chars in the middle boundary ([\d\w\"]+), such as this RegEx:
(\d+,){2}[\d\w\"]+(,)
and capture the third , using $2. This time you can also relax your expression from the right side, and it would still work.
You might also add a start ^ in the regex:
^(\d+,){2}[\d\w\"]+(,)
as an additional left boundary which means your input must start with this expression.