Multiple inheritance with multiple parents

Question

Base is superclass.
It has instance variable= sides.
It has show() method which gives value of sides.

Circle inherits Base.
It has show() method which prints classname.

Triangle inherits Base.
It has show() method which prints classname.

Square inherits Base.
It has show() method which prints classname.

Shape inherits Circle,Triangle,Square.
It has show() method which prints "i'm in shape"

We have to create an instance of the Shape class and access the show() method of Circle class using the instance created.

I want to access the show() method of Circle only and not the show() method of the Shape class.

How do I do that?

class Base:
    def __init__(self,sides):
        self.sides=sides

    def show(self):
        return self.sides

class Triangle(Base):
    def show(self):
        print("Triangle")

class Square(Base):
    def show(self):
        print("Square")

class Circle(Base):
    def show(self):
        print("Circle")

class Shape(Circle,Square,Triangle):
    def __init__(self):
        super(Shape,self).show()
    def show(self):
        print("i am in shape")

a=Shape()
a.show()

I was trying to get the output as:

Circle

But the code is giving me the output as:

Circle
i am in shape

how does the code change if i have to call show method of Circle class by a.show() by using the instance of Shape class?

So why are you calling `a.show()` as well as `super(Shape,self).show()` in `__init__`? — Martijn Pieters, Apr 27 '19 at 14:47
Calling `a=Shape()` will call the constructor, and will print `Circle`, why the extra `a.show()`? — Devesh Kumar Singh, Apr 27 '19 at 14:51
@Martjin Pieters i was thinking if i could access the show method of Circle by writing a.show() — Xesuxiona, Apr 27 '19 at 14:54

Devesh Kumar Singh · Accepted Answer · 2019-04-27T15:01:17.410

0

You should leave the super(Shape,self).show() as it is and just instantiate the Shape, which will print Circle as below. The exta a.show() you are calling is printing the extra i am in shape

class Shape(Circle,Square,Triangle):

    def __init__(self):
        super(Shape,self).show()

    def show(self):
        print("i am in shape")

#The constructor is called
a=Shape()
#Circle

#The show function of class Shape is called
a.show()
#i am in shape

If you want to explicitly access the show method of Circle, you need to instantiate that object.

a=Circle(2)
a.show()
#Circle

In addition, look at: How does Python's super() work with multiple inheritance? for more info on how super works for multiple inheritance

edited Apr 27 '19 at 15:01

answered Apr 27 '19 at 14:53

Devesh Kumar Singh

20,259
5
21
40

how do i call the show method of Circle class by writing a.show()? – Xesuxiona Apr 27 '19 at 14:56
how does the code change if i have to call show method of Circle class by a.show()? – Xesuxiona Apr 27 '19 at 14:57
By explicitly creating the object of class Circle! – Devesh Kumar Singh Apr 27 '19 at 15:00
is it possible to call the show method of Circle by making instance of Shape and then accessing by a.show() – Xesuxiona Apr 27 '19 at 15:04
No, since `a.show()` calls the show method of Shape, and not Circle! – Devesh Kumar Singh Apr 27 '19 at 15:06
Great! Please accept the answer if it helped you :) – Devesh Kumar Singh Apr 27 '19 at 15:13

Multiple inheritance with multiple parents

1 Answers1