The goal is that when sleep_time reaches 0.1 it starts a loop where it prints number.
import time
number = 0
sleep_time = 1
# Main code
while sleep_time >= 0.1:
if sleep_time == 0.1:
while True:
print(number)
number += 1
time.sleep(sleep_time)
print(number)
sleep_time -= 0.1
This prints numbers from 1 to 10 and then it stops.
This is an issue of floating-point imprecision, consider:
>>> sleep = 1
>>> dec = 0.1
>>> for _ in range(9):
... sleep -= dec
...
>>> sleep
0.10000000000000014
>>> sleep == 0.1
False
>>>
When dealing with this sort of thing, usually math.isclose is a viable solution:
>>> import math
>>> math.isclose(sleep, 0.1)
True
>>>
The following should be required reading
Other approaches would be to use only int objects, or to use decimal.Decimal.
This is due to floating point error.
x = 1.0
for _ in range(9):
x -= 0.1
print(x) # 0.10000000000000014
print(x == 0.1) # False
When exact arithmetic is required for a problem which handles an atomic quantity, it's better to use int than float. In this case your atomic quantity being a tenth of a second, we'll let 1 represent 0.1 second.
import time
number = 0
sleep_time = 10 # in tenth of seconds
# Main code
while sleep_time >= 1:
if sleep_time == 1:
while True:
print(number)
number += 1
time.sleep(sleep_time / 10)
print(number)
sleep_time -= 1