My for loop in python3.0 does not iterate fully?

Question

List of 4 items is given. I need to iteratively remove an item from the list. At each iteration I need to show: - What is removed - New list

I am trying this:

import random
teams=["Tottenham", "Ajax", "Barcelona", "Liverpool"] 
for i in teams:
    t1=random.randint(0, len(teams)-1)
    print(teams[t1])
    teams.remove(teams[t1])
    print(teams)

I am getting this:

Ajax

['Tottenham', 'Barcelona', 'Liverpool']

Liverpool

['Tottenham', 'Barcelona']

But should get something like this:

Ajax

['Tottenham', 'Barcelona', 'Liverpool']

Liverpool

['Tottenham', 'Barcelona']

Tottenham

['Barcelona']

you are removing items from the list you are iterating over... see here: https://stackoverflow.com/questions/6260089/strange-result-when-removing-item-from-a-list — hiro protagonist, May 01 '19 at 06:32
Please use the generic `python` tag on all Python questions. — PM 2Ring, May 01 '19 at 09:17

Cloudomation · Answer 1 · 2019-05-01T06:46:39.460

You can shuffle the list first, then iterate over it:

import random

teams = ["Tottenham", "Ajax", "Barcelona", "Liverpool"]
random.shuffle(teams)

while teams:
    print(teams.pop())
    print(teams)

Output

Liverpool
['Ajax', 'Tottenham', 'Barcelona']
Barcelona
['Ajax', 'Tottenham']
Tottenham
['Ajax']
Ajax
[]

Note

To shuffle first reduces the complexity of the loop. It might not be applicable in all situations, but it is an option.

My for loop in python3.0 does not iterate fully?

1 Answers1

Output

Note