Simple regular expression not matching number in Python3

Asked May 01 '19 at 23:02

Active May 01 '19 at 23:08

Viewed 19 times

I'm trying to match a number between 1 and 3 in a string using a regex:

import re

print(re.match(r'[1-3]{1}', 'a1')) # Prints None
print(re.match(r'[1-3]{1}', '1a')) # Prints <re.Match object; span=(0, 1), match='1'>

While my regex seems to be working correctly both on regex101.com and in JS, for some reason I cannot get it to work in Python3.

Can someone point me to what is wrong here?

edited May 01 '19 at 23:08

asked May 01 '19 at 23:02

Philippe Hebert

Thanks @wiktor-stribiżew for the answer :) – Philippe Hebert May 01 '19 at 23:05
2

Use `re.search`. BTW, `print(re.match(r'[1-3]{1}', '1a'))` [does not print None](https://ideone.com/nPp2C8). – Wiktor Stribiżew May 01 '19 at 23:05
Thanks, I'll update the question! – Philippe Hebert May 01 '19 at 23:08
1

`{1}` is a redundant quantifier in regex, synonymous with having nothing in its place. – CAustin May 01 '19 at 23:36

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