how to pass arguments in execution file using php

Question

When I supply arguments to my application it doesn't run. It does without arguments.

shell_exec('C:\Program Files\yrdy\yrdsy\yrdy\yr5dr.exe"/"  user=000"," -pw=123 ');

Please help me.

Possible duplicate of [Passing multiple PHP variables to shell\_exec()?](https://stackoverflow.com/questions/16932113/passing-multiple-php-variables-to-shell-exec) — Valentino, May 02 '19 at 12:23

NoobieNoob · Answer 1 · 2019-05-02T09:56:18.690

0

please in the future give us more details of you code.

To answer your question, you have to send the arguments with quota

for exemple :

$user=000;
$pw="-pw=123";
shell_exec('C:\Program Files\yrdy\yrdsy\yrdy\yr5dr.exe"/'" .$user."' '" .$pw."'");

Tell us if it helps you.

edited May 02 '19 at 09:56

answered May 02 '19 at 09:49

NoobieNoob

its not working any other solution in command my exe with aruguments is working but passing with php is not working – vikathi May 02 '19 at 10:12
Did you try to debug to check where you code stop running ? – NoobieNoob May 02 '19 at 11:06
i didn't know how to bug.. i tried in command it work properly – vikathi May 02 '19 at 11:08

1 Answers1