How to split integers with a comma

Question

I want to print all of the integers in the range 1000-3000 that are even and then print them in one line, each seperated by a comma. This is my code so far:

for i in range (1000,3001):
      s = str(i)
      if i % 2 == 0:
            print (i)

If I try to add the split() function, this error occurs: 'int' object has no attribute 'split'

How can I do this?

It helps to understand what given function does before trying to use it. Shotgun development barely works. — Marcin Orlowski, May 04 '19 at 18:05
Possible duplicate of [Print new output on same line](https://stackoverflow.com/questions/12032214/print-new-output-on-same-line) — Sheldore, May 04 '19 at 18:06
Given that it's not a massive range... you could probably get away with: `print(*range(1000, 3001, 2), sep=',')` here — Jon Clements, May 04 '19 at 18:08

ruohola · Answer 1 · 2019-05-04T18:19:10.367

2

As simple as:

print(','.join([str(i) for i in range(1000, 3001, 2)]))

Or alternatively:

print(*range(1000, 3001, 2), sep=',')

You don't need to check for even numbers, since you can just print every second number starting with an even number.

edited May 04 '19 at 18:19

answered May 04 '19 at 18:12

ruohola

21,987
6
62
97

score 0 · Answer 2 · answered May 04 '19 at 18:22

0

Te answer to this is as simple as follows:

out = [str(i) for i in range(1000, 3001) if i % 2 == 0]

print(",".join(out))

The output reads:

1000, 1002, ..., 3000

answered May 04 '19 at 18:22

pdrersin

311
3
10

score -1 · Answer 3 · answered May 04 '19 at 18:12

Try this, it works fine :

even_number_list=[]    # taking an empty list to store even numbers

for i in range(1000,3001):
        if(i%2==0):
                even_number_list.append(i)   # appending even numbers in our list

print(*even_number_list,sep=',')            # unpacking list with values seperated by comma

How to split integers with a comma

3 Answers3