Echo the names of all cookies

Asked May 07 '19 at 16:03

Active May 07 '19 at 16:08

Viewed 16 times

I'm using this code to display a list of the names of all cookies (not values):

foreach ($cookies as $key=>$item){
    if (is_numeric($key)) {
        echo "$key,";
    }
}

That is working correctly. But, I'm trying to assign the full results to a variable that can be used later on in my code. I just need it to be a list of the cookie names, separated by a comma.

I tried turning it into a function and assigning it to a variable like this:

$cookies = $_COOKIE;
function get_cookies() {
    foreach ($cookies as $key=>$item){
        if (is_numeric($key)) {
            return "$key,";
        }
    }
}

$all_cookies = get_cookies();

echo $all_cookies;

But when I do that, I'm getting this error:

Warning: Invalid argument supplied for foreach()

What exactly am I doing wrong?

asked May 07 '19 at 16:03

Stacker

2

`$cookies` is defined outside the function so the function doesn't know about it. Pass it as a parameter or just use `$_COOKIES` (*not* `$_COOKIE`) in the function. – miken32 May 07 '19 at 16:06
1

`function get_cookies($cookies)` – Felippe Duarte May 07 '19 at 16:07
You want "all" cookies or the first numeric indexed one? – user3783243 May 07 '19 at 16:09
1

If you wanted *all* of the cookies names wouldn't `array_keys()` be a better choice? – Nigel Ren May 07 '19 at 16:10
echo implode(',' array_keys($cookies) ); – Max May 07 '19 at 16:11

Echo the names of all cookies

0 Answers0