How to convert decimal to hex in string format

Question

Hi let's say I have 5 decimal numbers.How can I convert them firstly to hexadecimal and to string afterwards. Is there any built in function for this? I tried below

numbers = [123,46,0,11,6]
for number in numbers:
    print(hex(number).lstrip("0x").upper())

Expected output is

7B
2E
00
0B
06

but the result is

7B
2E

B
6

`strip` will remove all characters inside the string you give it as an argument. So `"0x00".strip("0x")` will leave you an empty string. Just slice the string like `hex(number)[2:]` — isaactfa, May 08 '19 at 19:52

score 0 · Answer 1 · answered May 08 '19 at 19:51

0

Add zfill:

numbers = [123,46,0,11,6]
for number in numbers:
    print(hex(number).lstrip("0x").zfill(2).upper())

answered May 08 '19 at 19:51

Michael H.

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1

It's much simpler with format: `format(number, "02X")`. – Mark Dickinson May 08 '19 at 20:02
Nice. That's worth a separate answer. – Michael H. May 08 '19 at 20:07

How to convert decimal to hex in string format

1 Answers1