Ordering a set in base python

Question

Is there a way of ordering a set in base python?

For example:

A = {1, 2, 3}
B = {3, -6, 2, 0}
print union(A, B)

Expected Output:

({-6, 0, 1, 2, 3}, 5)

My attempt:

x = A | B
y = len(x)
print((set(x), y))

My output:

({0, 1, 2, 3, -6}, 5)

I have read some of the answers for other questions and there are ways of doing it with various packages, but for this exercise, I am NOT meant to import any packages, just doing it in base python (if that is what it is called) if possible.

`set`s are inherently not ordered data structure, you may use a sorted list — Chris_Rands, May 09 '19 at 10:03
This might be what you are looking for: https://stackoverflow.com/questions/1653970/does-python-have-an-ordered-set — trotta, May 09 '19 at 10:03

score 1 · Answer 1 · answered May 09 '19 at 10:04

1

No, sets are unordered by definition and implementation. To create a sorted list, convert your set to a list and sort it:

List = sorted(your_set)

answered May 09 '19 at 10:04

ForceBru

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Sort of works, but when it is converted back to a set, it is unsorted again. – william3031 May 09 '19 at 10:13
2

@william3031, sets are __unordered__. There's _no way_ to sort a set. – ForceBru May 09 '19 at 10:15
No worries. Thanks. I am just wondering how to get to the expected output. – william3031 May 09 '19 at 10:18

Ordering a set in base python

1 Answers1