how do i get another variable from different php file into another file?

Question

I listed all Country names in "countries.php", like:

<?php
$countryArray = array(
    'AD'=>array('name'=>'ANDORRA','code'=>'376'),
    'AE'=>array('name'=>'UNITED ARAB EMIRATES','code'=>'971'), ...
);
function countrySelector($defaultCountry = "", $id = "", $name = "", $classes = ""){
    global $countryArray; // Assuming the array is placed above this function

    $output = "<select id='".$id."' name='".$name."' class='". $classes."'>";
    $output .= "</select>";
}

using the file in "signup.php", well this works but, what I want to do is to create input (mobile number) in "signup.php", In the mobile input, I want to use a country code when a user chooses a country, It will insert the country code into mobile input. Like: user chose US +1.. in the other input it will show +1(and the user can type their own number without adding the country-code by their self) I have also done the mobile validation properly. I have no idea how to do the code. please help.

If the array is used only in this function, then just put the array definition inside the function. — Alex Howansky, May 09 '19 at 14:02
You should make a database table `country` in which you can put those values. Then call that table values in whichever file you want. — G_real, May 09 '19 at 14:12
I already have the country in my table and how can i use that global? it's not helping me at all, or i dont know how to use it — Siavash Hosseini, May 09 '19 at 15:38

score 0 · Answer 1 · answered May 09 '19 at 14:08

0

You should read up on Classes. If you define your script in a class you access the variables by first calling use myClass and then accessing the variable statically or by creating an instance of your class object.

For example here you should create Country class and have your $countryArray as a static variable in that class that you could access using Country::$countryArray

Here's how your Country class would look:

class Country { 
    public $countryArray = ['usa', 'canada']; 
}

Then in your other script you could like so:

use Country;

$countries = Country::$countryArray;

answered May 09 '19 at 14:08

Ross

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in the second one i dont need to include anything? like i have the – Siavash Hosseini May 09 '19 at 15:41
For `use` to work you should working within a `namespace`, it's not commonly used in PHP. This questions goes into a little more detail on the differences: https://stackoverflow.com/questions/10965454/how-does-the-keyword-use-work-in-php-and-can-i-import-classes-with-it Are you using any framework here or is it vanilla PHP scripts? – Ross May 09 '19 at 16:25
Assuming you had `countrySelector()` as a function in your `Country` class, you call it on your view file as = Country::countrySelector($id, $name, $classes) ?> – Ross May 09 '19 at 16:27

how do i get another variable from different php file into another file?

1 Answers1