passing a sequence into varargs method that does not use type ascription

Question

I am working with a third party library and am trying to do some abstractions and am running into an issue with a method that accepts varargs but is not using type ascription. Something like:

  def outer(otherStuff:String*): Unit ={
    if(someCondition)
      methodInThirdPartyLibrary(otherStuff)
    // other code....
  }

  def methodInThirdPartyLibrary(stuff:String*): Unit ={
    println(stuff.mkString(","))
  }

Given how the library has the method setup is there any way for me to pass in the arguments?

Your question is unclear to me. Can you explain what it means that the method "accepts varargs but is not using type ascription"? Why would it matter whether the method uses type ascription or not? — Jörg W Mittag, May 11 '19 at 03:45

Krzysztof Atłasik · Accepted Answer · 2019-05-10T17:42:35.913

6

You just need to use special :_* spread ascription:

def outer(otherStuff:String*): Unit ={
   if(someCondition)
     methodInThirdPartyLibrary(otherStuff: _*)
   // other code....
}

Also check out this anwser.

edited May 10 '19 at 17:42

answered May 10 '19 at 17:32

Krzysztof Atłasik

21,985
6
54
76

I do not have control over the method in the third party library. I would only have control of the outer method. – adambsg May 10 '19 at 17:39
@adambsg I edited my answer because it might have looked ambiguous. – Krzysztof Atłasik May 10 '19 at 17:43
2

Thanks for the link, where it's called the smooch operator. Ha. Oh, also now I just saw how someone could misunderstand where it goes. – som-snytt May 10 '19 at 17:44

passing a sequence into varargs method that does not use type ascription

1 Answers1