printing to multiple lines at the same time python

Question

I am making a text based game and I am trying to print this code one character at a time on each column.

'''###############

Let us begin...

###############'''

I can't figure out how to make it come out one column at a time.

Possible duplicate of [How to print multiple lines of text with python](https://stackoverflow.com/questions/34980251/how-to-print-multiple-lines-of-text-with-python) — M--, May 11 '19 at 00:35

score 1 · Answer 1 · answered May 11 '19 at 00:50

Well, I still felt like answering this despite the vagueness of your question. Maybe this is what you are looking for, this prints one column at a time (one character per row):

import subprocess
import platform
from time import sleep


def clear_screen():
    # thanks to: https://stackoverflow.com/a/23075152/2923937
    if platform.system() == "Windows":
        subprocess.Popen("cls", shell=True).communicate()
    else:
        print("\033c", end="")


# obviously you can create a function to convert your string into this
# list rather than doing it manually like I did, but that is another question :p.
views = ['#\nh\n#', '##\nhe\n##', '###\nhel\n###', '####\nhell\n####', '#####\nhello\n#####']

for view in views:
    clear_screen()
    print(view)
    sleep(0.5)

Thank you, this is what I had meant. – Dulnefni May 11 '19 at 03:18 — Dulnefni, May 11 '19 at 03:18
It was a gamble, glad I could be of assistance. – Perplexabot May 11 '19 at 03:20 — Perplexabot, May 11 '19 at 03:20

score 0 · Answer 2 · answered May 11 '19 at 01:06

If you are already doing print(c, end='') for each character in you string, just add flush=True to the call to print(). The sleep call will introduce enough delay so that you can see the characters print one at a time:

>>> import time
>>> s = '''###############
... Let us begin...
... ###############'''
>>> for c in s:
...    print(c, end='', flush=True)
...    time.sleep(0.1)

printing to multiple lines at the same time python

2 Answers2