preg_replace output is not correct

Asked May 11 '19 at 12:28

Active May 11 '19 at 12:28

Viewed 16 times

I have this example.

$link='http://www.mylink.com';
$string= 'You have confirmed your account. <br /> Please click {here} to log in';
echo preg_replace('/(\[(.+)\])/', '<a href="' . $link . '">$2</a>', $string);

and the output is:

You have confirmed your account. Please click {here} to log in

What is the problem?

asked May 11 '19 at 12:28

Amir

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You need `preg_replace('/{(.*?)}/', '$1', $string)`. Your match is inside curly braces, not square brackets. See https://3v4l.org/JOhOh – Wiktor Stribiżew May 11 '19 at 12:29
@WiktorStribiżew, thank you so much. what about `preg_replace('/(\[(\w*)\])/', '$2', $string);` ? – Amir May 11 '19 at 12:35
The same here, but less generic in general, and it has a redundant capturing group around the whole pattern. You do not need that group. – Wiktor Stribiżew May 11 '19 at 12:39
@WiktorStribiżew, Many thanks, now everything is ok. – Amir May 11 '19 at 12:44

preg_replace output is not correct

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