How to make numbers from a list of permutations?

Question

The program gets 5 random numbers(0-9).I generated permutations into a list. An example: numbers: 0,1,2,3,4 list = [(1,0,2,3,4),(1,0,2,4,3),...] and I would like to get: list = [10234,10243,...] And have to make an exception for 0, of course numbers can't start with 0. Only 5 digit numbers are accepted. So from the example can't get 1234, because 0 must be included everywhere except for the first.

import numpy as np
import itertools


m = np.random.randint(0,10,5)
m = list(m)
print(m)

x = set(itertools.permutations(m))
print(x)

Possible duplicate of [Join a list of items with different types as string in Python](https://stackoverflow.com/questions/3590165/join-a-list-of-items-with-different-types-as-string-in-python) — Sheldore, May 11 '19 at 16:52

yatu · Accepted Answer · 2019-05-11T17:10:37.603

2

I believe you can simply add:

list(map(int,(''.join(map(str,i)) for i in list(x) if i[0] != 0)))
# [44757, 44577, 47574, 74745, 74475,...

edited May 11 '19 at 17:10

answered May 11 '19 at 16:46

yatu

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Yep, I think that's the most concise way – Ahmad Moussa May 11 '19 at 16:56
This isn't good because only 5 digit numbers are accepted and this got 4 digit numbers as well. – BeginnerGuy012 May 11 '19 at 17:07
Check now @BeginnerGuy012 – yatu May 11 '19 at 17:10

How to make numbers from a list of permutations?

1 Answers1