Generating Unique Random Strings

Question

I want to create a code that would generate number of random strings (for eg.10 in this case). I used the code below but the code kept on generating same strings

Input Code

import random
import string

s = string.ascii_lowercase
c = ''.join(random.choice(s) for i in range(8))

for x in range (0,10):
    print(c)

Output

ashjkaes
ashjkaes
ashjkaes
ashjkaes
ashjkaes
ashjkaes
ashjkaes
ashjkaes
press any key to continue .....

Please help

You need to put the `random.choice` in the `for` loop to make a new one each time. — Mark, May 11 '19 at 18:19

David Sidarous · Accepted Answer · 2019-05-11T18:56:58.603

7

What you do now is you generate a random string c then print it 10 times You should instead place the generation inside the loop to generate a new string every time.

import random
import string

s = string.ascii_lowercase

for i in range(10):
    c = ''.join(random.choice(s) for i in range(8))
    print(c)

edited May 11 '19 at 18:56

answered May 11 '19 at 18:21

David Sidarous

1,202
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1

There is no guarantee that the strings will be unique. While pretty low, there is a chance a string will be generated twice – Tomerikoo May 30 '21 at 11:42

score 2 · Answer 2 · answered May 11 '19 at 18:47

2

Since Python 3.6, you can use random.choices (see this answer). Example:

import random
import string

sample = "".join(random.choices(string.ascii_lowercase, k=10))
print(sample)

answered May 11 '19 at 18:47

Joel Cornett

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score 2 · Answer 3 · answered May 11 '19 at 19:11

As already noted, you need to have random.choice inside loop, what I want to note, that you could use underscore (_) meaning I do not care for that variable together with for, which in this case would mean:

import random
import string

s = string.ascii_lowercase
for _ in range(10):
    c = ''.join(random.choice(s) for _ in range(8))
    print(c)

I do not want you to feel obliged to do so, but be aware about such convention exist in Python language.

score 1 · Answer 4 · edited May 11 '19 at 18:40

1

Try below to achieve result what you want

import random
import string

s = string.ascii_lowercase

for x in range (0,10):
    print(''.join(random.choice(s) for i in range(8)))

edited May 11 '19 at 18:40

VRAwesome

4,721
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answered May 11 '19 at 18:22

DoomSkull

36
4

score 1 · Answer 5 · answered May 11 '19 at 19:23

This will give you random string including numbers, uppercase and lowercase letters.

import string, random
random_string=''
for x in range(8):
    if random.choice([1,2]) == 1:
        random_string += random_string.join(random.choice(string.ascii_letters))
    else:
        random_string += random_string.join(random.choice(string.digits))
print(random_string)

Generating Unique Random Strings

5 Answers5