Getting indexes of all max values in a list

Question

Is there any way in Python to get all indexes of elements which contain max value of a list?

I've tried this:

list = [1, 3, 2, 2, 1, 1, 1, 2, 3, 2, 1, 1, 1, 3, 1, 1, 3]
m = list.index (max(list))

But this returns only the first index of all of those which have max value.

Yeah, I obviously do, just changed a name to clarify my question. Thanks — MLapaj, May 12 '19 at 21:09

score 4 · Answer 1 · answered May 12 '19 at 21:04

4

Try this :

l = [1, 3, 2, 2, 1, 1, 1, 2, 3, 2, 1, 1, 1, 3, 1, 1, 3]
mx = max(l)
m = [i for i,j in enumerate(l) if j==mx]

OUTPUT :

[1, 8, 13, 16]

answered May 12 '19 at 21:04

score 2 · Answer 2 · answered May 12 '19 at 21:04

2

You can compute the max then use a list comprehension to get the indices where the max is found:

l = [1, 3, 2, 2, 1, 1, 1, 2, 3, 2, 1, 1, 1, 3, 1, 1, 3]
x = max(l)

m = [i for i in range(len(l)) if l[i] == x]

print(m)

Output:

[1, 8, 13, 16]

answered May 12 '19 at 21:04

DjaouadNM

2 Answers2