what should be filled up so the code can run successfully?

Question

import java.util.*;   

public class Main
{
  public static void main(String[] args) 
  {
      List student = new ArrayList();
      student.add("123");
      student.add("ABC");
      student.add("70.8");    

      Iterator itr = listItr.iterator();

      while(itr.hasNext())      
      {
          System.out.println(itr.next()); 

      }
 }

} What should i write here Iterator itr = _________; in order to get an output?

Please see [What is a raw type and why shouldn't we use it?](https://stackoverflow.com/q/2770321/1361506) — azurefrog, May 14 '19 at 22:09
Are you struggling to see where standard out (System.out.println) prints to? I think this code will successfully print to standard out. — cellepo, May 14 '19 at 22:22
Please change the title and make sure address the issue more clearly and what you want it to be. — Adan Vivero, May 14 '19 at 23:21

score 0 · Answer 1 · answered May 14 '19 at 22:09

You are trying to iterate over nothing :

// specify a list type with <yourType>
List<String> students=new ArrayList<String>();
// fill up your list

// was Iterator it = listItr.iterator(); but listItr is nothing
Iterator<String> it=students.iterator();
while(it.hasNext()) {
    System.out.println(it.next());
}

score 0 · Answer 2 · answered May 14 '19 at 22:32

0

Generics aside, you only have to change this line:

Iterator itr = listItr.iterator();

to this:

Iterator itr = student.iterator();

answered May 14 '19 at 22:32

Jason

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what should be filled up so the code can run successfully?

2 Answers2