Ajax undefenided post

Asked May 14 '19 at 23:18

Active May 14 '19 at 23:32

Viewed 18 times

i dont know whats appen whit my code some can help?

my code:

<script src="https://code.jquery.com/jquery-2.1.1.min.js" type="text/javascript"></script>
<script type="text/javascript">  
function sendmessage() {
    var namesd = $("#namesd").val();
    var dataString = {"name":namesd};
    alert(dataString);
    $.ajax({
        type:"post",
        url: "submitmessage.php",
        data: dataString,
        cache: false,
        success: function(html){
                $('#alert_sucess').html(html);
            }
        });
        return false;
    }
</script>

<form>
    <input type='text' id='namesd' name='name' />
   <input type='submit' value='submit' onclick="return sendmessage()"  />
</form>
<div id='alert_sucess'></div>

my submitmessage.php

if(isset($_POST['name'])) {
echo "name ".$_POST['name'];
} else {
echo "no post ";
}

on submit show alert whit values but return dont have post

edited May 14 '19 at 23:32

asked May 14 '19 at 23:18

x3G

Where is `alert_sucess ` defined ? – Dimitri Mockelyn May 14 '19 at 23:20
i forget post, is after form i go update – x3G May 14 '19 at 23:22
You have to give the input a name attribute: `name="name"` – Jay Blanchard May 14 '19 at 23:23
yes i put now and dont work same... sorry for my old quest xD – x3G May 14 '19 at 23:27
you should add `dataType : 'json'` on your ajax request. – Conan May 14 '19 at 23:44
@Conan hi, i put now and dont return nothing i go. data: dataString, cache: false, dataType : 'json', – x3G May 14 '19 at 23:50
@x3G try this `$.ajax({ type:"post",dataType : 'json', url: "submitmessage.php", data: dataString }).done(function(html){ $('#alert_sucess').html(html); });` – Conan May 14 '19 at 23:58
@Conan dont post nothing dont say nothing – x3G May 14 '19 at 23:59
@x3G ok wait a moment.. – Conan May 15 '19 at 00:01
Try to use this in your php `$req = file_get_contents('php://input'); $reqParams = json_decode($req,TRUE);` and then make your condition like this `if(isset($reqParams['name'])) ` – Conan May 15 '19 at 00:05
again dont say nothing :s – x3G May 15 '19 at 00:07
No error nothing ?!! – Conan May 15 '19 at 00:09
nothing.. i can try add error for see error say – x3G May 15 '19 at 00:09
on code bellow, on error say this: textStatus: open:35:25 parsererror open:36:25 errorThrown: open:37:25 SyntaxError: "JSON.parse: unexpected character at line 2 column 1 of the JSON data" – x3G May 15 '19 at 00:11

Ajax undefenided post

0 Answers0