get the name of the key that has the highest property value in nested javascript objects,

Question

var food = {
"fruit":{"brand":{"grgrdgdr":true,"ggyugy":true}, "sold":2},
"vegetable" :{"brand":{"htrhtr":true},"sold": 1},
"snack":{"brand":{"htrhr":true},"sold": 3},
"other":{"brand":{"gdhshd":true},"sold":1},
....
...
...

};

How do I console log the object name that sold the most, in this case should be the word snack.

I find this link, but its structure is not similar to mine. Get object keys with the highest value in Javascript

any help is appreciated thanks in advance

if they have they same top value, choose anyone of key name that has those top same value — Tosps, May 15 '19 at 12:01
Dupe code to change is `.sort(function(a, b) { return food[b].sold - food[a].sold; })[0]` — mplungjan, May 15 '19 at 12:15

score 1 · Accepted Answer · answered May 15 '19 at 12:06

1

You could sort by the values property and get the first item.

var food = { fruit: { brand: { grgrdgdr: true, ggyugy: true }, sold: 2 }, vegetable: { brand: { htrhtr: true }, sold: 1 }, snack: { brand: { htrhr: true }, sold: 3 }, other: { brand: { gdhshd: true }, sold: 1 } };
    result = Object
        .keys(food)
        .sort((a, b) => food[b].sold - food[a].sold)
        [0];

console.log(result);

answered May 15 '19 at 12:06

Nina Scholz

376,160
25
347
392

Yeah, like the link he posted. – mplungjan May 15 '19 at 12:13

score 1 · Answer 2 · answered May 15 '19 at 12:07

Find the max value first, and then filter the object to get objects having max sold value

var food = {
"fruit":{"brand":{"grgrdgdr":true,"ggyugy":true}, "sold":2},
"vegetable" :{"brand":{"htrhtr":true},"sold": 1},
"snack":{"brand":{"htrhr":true},"sold": 3},
"other":{"brand":{"gdhshd":true},"sold":1}}

var maxSold = Math.max(...Object.values(food).map(o=> o.sold))

var result = Object.keys(food).filter(o => food[o].sold ===maxSold)
console.log(result) //this will given all objects with max sold value

score 0 · Answer 3 · answered May 15 '19 at 12:06

You can use a variable & iterate the array twice. In the first iteration get the highest sold. Then on second iteration add the products whose sold value is same as the highest sold

var food = {
  "fruit": {
    "brand": {
      "grgrdgdr": true,
      "ggyugy": true
    },
    "sold": 5
  },
  "vegetable": {
    "brand": {
      "htrhtr": true
    },
    "sold": 1
  },
  "snack": {
    "brand": {
      "htrhr": true
    },
    "sold": 3
  },
  "other": {
    "brand": {
      "gdhshd": true
    },
    "sold": 1
  },
  "someOtherfruit": {
    "brand": {
      "grgrdgdr": true,
      "ggyugy": true
    },
    "sold": 5
  }
}

let highestSold = 0;
let newObj = [];

for (let keys in food) {
  if (food[keys].sold > highestSold) {
    highestSold = food[keys].sold
  }
}

for (let keys in food) {
  if (food[keys].sold === highestSold) {
    newObj.push(food[keys])
  }
}

console.log(newObj[0])

mplungjan · Answer 4 · 2019-05-15T12:16:42.077

Your posted link Get object keys with the highest value in Javascript

was quite close

var food = {
"fruit":{"brand":{"grgrdgdr":true,"ggyugy":true}, "sold":2},
"vegetable" :{"brand":{"htrhtr":true},"sold": 1},
"snack":{"brand":{"htrhr":true},"sold": 3},
"other":{"brand":{"gdhshd":true},"sold":1}
  },
  result = Object
  .keys(food)
  .sort(function(a, b) {
    return food[b].sold - food[a].sold;
  })[0] // or  .slice(0, 1); 

console.log(result,food[result]);

.as-console-wrapper {
  max-height: 100% !important;
  top: 0;
}

score 0 · Answer 5 · edited May 15 '19 at 12:14

0

var food = {
"fruit":{"brand":{"grgrdgdr":true,"ggyugy":true}, "sold":2},
"vegetable" :{"brand":{"htrhtr":true},"sold": 1},
"snack":{"brand":{"htrhr":true},"sold": 3},
"other":{"brand":{"gdhshd":true},"sold":1},
};


function getMostExpensivesKey(array) {
  let key = Object.keys(array)[0];

  Object.keys(array).forEach(function(k) {
    if(array[k].sold > array[key].sold) {
      key = k;
    }
  });

  return key;
}


console.log(getMostExpensivesKey(food));

edited May 15 '19 at 12:14

mplungjan

169,008
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answered May 15 '19 at 12:14

PopHip

700
6
23

note that this function will return the first key, if you want the last one change to >= – PopHip May 15 '19 at 12:15

get the name of the key that has the highest property value in nested javascript objects,

5 Answers5