I want all the dates of the present week based on weeknumber.
I can get week number like
import datetime
weeknum=datetime.datetime.now().isocalendar()[1]
result is 20.
wanted all dates of week 20. the final output should be
dates=['2019-05-12','2019-05-13','2019-05-14','2019-05-15','2019-05-16','2019-05-17','2019-05-18']
please help me.
You can do it with time and datetime as well as this answer suggest but change it to your requirements:
WEEK = 20 - 2 # as it starts with 0 and you want week to start from sunday
startdate = time.asctime(time.strptime('2019 %d 0' % WEEK, '%Y %W %w'))
startdate = datetime.datetime.strptime(startdate, '%a %b %d %H:%M:%S %Y')
dates = [startdate.strftime('%Y-%m-%d')]
for i in range(1, 7):
day = startdate + datetime.timedelta(days=i)
dates.append(day.strftime('%Y-%m-%d'))
Output as following:
dates = ['2019-05-12',
'2019-05-13',
'2019-05-14',
'2019-05-15',
'2019-05-16',
'2019-05-17',
'2019-05-18']
Use timedelta and a list comprehension.
import datetime
theday = datetime.date.today()
weekday = theday.isoweekday()
# The start of the week
start = theday - datetime.timedelta(days=weekday)
# build a simple range
dates = [start + datetime.timedelta(days=d) for d in range(7)]
To get output in strings
dates = [str(d) for d in dates]
import datetime
# Starts with knowing the day of the week
week_day=datetime.datetime.now().isocalendar()[2]
# Calculates Starting date (Sunday) for this case by subtracting current date with time delta of the day of the week
start_date=datetime.datetime.now() - datetime.timedelta(days=week_day)
# Prints the list of dates in a current week
dates=[str((start_date + datetime.timedelta(days=i)).date()) for i in range(7)]
dates
The Output is:
>>> dates
['2019-05-12', '2019-05-13', '2019-05-14', '2019-05-15', '2019-05-16', '2019-05-17', '2019-05-18']
Hope this can help you. Have a nice day. :D
Simply you can use python fromisocalendar() function
year = 2023
week = 12
startdate = datetime.date.fromisocalendar(year, week, 1)
dates = []
for i in range(7):
day = startdate + datetime.timedelta(days=i)
dates.append(day)
the output will be:
[
"2023-03-20",
"2023-03-21",
"2023-03-22",
"2023-03-23",
"2023-03-24",
"2023-03-25",
"2023-03-26"
]
I would take a look at both of the below questions. The first should help you to calculate the starting date given a week number - don't forget to specify your year.
I would then use the below answer and instead of using a start/end date, use your start date from above and add 1 day; 6 times and store each new date in an array.
What you can do is this -
weekdates = []
week_number = datetime.datetime.now().isocalendar()[1]
for day in range(7):
week_date = datetime.datetime.strptime("2019-W{}".format(week_number)+ '-{}'.format(day), "%Y-W%W-%w")
weekdates.append(week_date)
What this does is, this leverages the date format conversion to construct a date according to the day in the week.
Hope this helps.
For those who need the output dates to start from a monday can tweak it like this:
import time
import datetime
WEEK = 20 - 1 # as it starts with 0 and you want week to start from sunday
startdate = time.asctime(time.strptime('2019 %d 1' % WEEK, '%Y %W %w'))
startdate = datetime.datetime.strptime(startdate, '%a %b %d %H:%M:%S %Y')
dates = [startdate.strftime('%Y-%m-%d')]
for i in range(1, 7):
day = startdate + datetime.timedelta(days=i)
dates.append(day.strftime('%Y-%m-%d'))
print(dates)
Take the previous 14 days, the current day, and the following 14 days as candidates. Finally, check for which date week number is similar to the current week number:
import datetime
def week_to_dates():
date = datetime.date.today()
week = date.strftime("%V")
candidates = [date - datetime.timedelta(days=k) for k in range(14, 0, -1)] + \
[date] + \
[date + datetime.timedelta(days=k) for k in range(1, 15)]
return [candidate.strftime('%Y-%m-%d') for candidate in candidates if candidate.strftime("%V") == week]
