3

What is the syntax for doing something like this? When I try to compile the code below it tells me that a ';' was expected before '*', pointing to the return type of the function, ResourceManager<T>::ResourceWrapper*.

template<class T>
class ResourceManager
{
  private:
    struct ResourceWrapper;
    ResourceWrapper* pushNewResource(const std::string& file);
};

// (Definition of ResourceWrapper not shown.)

template <class T>
ResourceManager<T>::ResourceWrapper* ResourceManager<T>::pushNewResource(
    const std::string& file)
{
    // (Irrelevant details)
}
Paul Manta
  • 30,618
  • 31
  • 128
  • 208

1 Answers1

10

You are missing the typename keyword. See this question for more details on why typename is required. This code should compile:

template<class T>
class ResourceManager
{
  private:
    struct ResourceWrapper;
    ResourceWrapper* pushNewResource(const std::string& file);
};

// (Definition of ResourceWrapper not shown.)

template <class T>
typename ResourceManager<T>::ResourceWrapper* ResourceManager<T>::pushNewResource(
^^^^^^^^    const std::string& file)
{
    // (Irrelevant details)
}
Community
  • 1
  • 1
Naveen
  • 74,600
  • 47
  • 176
  • 233