How do I match string using regex when there is small bracket in string?

Question

Suppose, I have two strings:

A = 'Ecology (miscellaneous)'
B = 'Ecology (miscellaneous)'

I want to find whether they match or not using regular expressions.if (A == B) works fine, but, I want to use regex.

re.match (A,B)

This does not work because of small brackets in the string. What is the best way to do it?. I am not used to with regular expressions; I am learning.

[This might be relevant](https://stackoverflow.com/questions/18935754/how-to-escape-special-characters-of-a-string-with-single-backslashes) — Green Cloak Guy, May 16 '19 at 19:39
What *regex* did you try? also, this is **one** string, could you share more? Otherwise the *regex* might not match them all. For your case: `A = 'Ecology \(miscellaneous\)'` — CristiFati, May 16 '19 at 19:39

ruohola · Accepted Answer · 2019-05-16T19:52:25.843

0

You can simply use re.escape on the one string you want to treat as the pattern and just pass the other as is:

import re

A = 'Ecology (miscellaneous)'
B = 'Ecology (miscellaneous)'

print(bool(re.match(re.escape(A), B)))

Output:
True

edited May 16 '19 at 19:52

answered May 16 '19 at 19:42

ruohola

1 Answers1