ES6 Filter array of object were a property exists

Question

I am trying to filter an array of objects to return just the objects that have property the other objects do not have. Not a value in a property, but the property itself.

results [
   { 
      "title": "Foo",
      "value":  34
   },
   {
       "value": 43
   },
   {
       "title": "The Title",
       "value": 99
]

In the example above I want the first and last object as they have a 'title' property, in an new array of objects.

I looked at 'filter' but it seems to work with values.. How do I this?

Thanks

Fatih Turgut · Accepted Answer · 2021-02-12T15:19:23.537

7

You can filter items like following code, it filters if title property exists.

    const items = [
       { 
          "title": "Foo",
          "value":  34
       },
       {
           "value": 43
       },
       {
           "title": "The Title",
           "value": 99
       }
    ];
    

    const filteredItems = items.filter(item => !!item.title)

edited Feb 12 '21 at 15:19

answered May 17 '19 at 08:10

Fatih Turgut

319
3
9

What does !! mean in JS? – Ilija Iličić Nov 23 '21 at 12:00
@IlijaIličić https://stackoverflow.com/questions/784929/what-is-the-not-not-operator-in-javascript – Fatih Turgut Nov 23 '21 at 12:26

kli · Answer 2 · 2021-04-07T22:29:54.797

4

Use Boolean wrapper, it's more clear:

const filteredItems = items.filter(item => Boolean(item.title))

edited Apr 07 '21 at 22:29

answered Feb 02 '21 at 20:23

kli

456
3
12

ES6 Filter array of object were a property exists

2 Answers2