ES6 array destructuring for specific index

Question

I have an Array const arr = new Array(100).

And I set

arr[0] = 'A'
arr[49] = 'X'

When destructuring the 1st element, I can do it like:

let [first] = arr

How the statement would be like if I want to access to the 50th element by destructuring expression?

I know, but you wouldn't use destructuring to get the 50th element @NullDev — baao, May 17 '19 at 08:30
@bambam What if it's an interview question? It certainly is possible to do it in JS. You can always suggest to use arr[50] as side note in your answer. — NullDev, May 17 '19 at 08:32
@connexo yea, `destructuring` (I typed it two times :) thanks) — LiuWenbin_NO., May 17 '19 at 08:42
I ran into the issue because ESLint notifies me to use destructuring while I am going to use `let key = arr[3]`. — LiuWenbin_NO., May 17 '19 at 08:44

Kobe · Accepted Answer · 2022-01-19T08:39:38.400

11

You can grab the element using object destructuring, like so:

const arr = Array(50).fill(0).map((_, i) => `Element ${i + 1}`)

const {49: fifty} = arr
console.log(fifty)

edited Jan 19 '22 at 08:39

answered May 17 '19 at 08:29

Kobe

can the index by dynamic? – capr Jun 06 '23 at 15:17
@capr Can you be more specific? Destructuring like this isn't common, just use bracket notation like `arr[index]`. – Kobe Jun 07 '23 at 17:54

1 Answers1