How can I format timedelta microseconds to 2 decimal digits?

Question

Running this

import time
import datetime

timenow = time.time()
timedifference = time.time() - timenow
timedifference = datetime.timedelta( seconds=timedifference )
print( "%s" % timedifference )

I got this:

0:00:00.000004

How can I format trimming the microseconds to 2 decimal digits using the deltatime object?

0:00:00.00

Related questions:

The too obvious (and wrong) solution would be to use string slicing. — Antti Haapala -- Слава Україні, May 17 '19 at 19:23
Works like a charm! `timedifference = str(timedifference)[:-4]` — Evandro Coan, May 17 '19 at 19:55
I already had seen it. I showed `0:0` or something like it. But it is fine. — Evandro Coan, May 18 '19 at 15:49

Marc Compere · Answer 1 · 2020-05-11T00:22:31.360

3

Convert the timedifference to a string with str(), then separate on either side of the decimal place with .split('.'). Then keep the first portion before the decimal place with [0]:

Your example with the only difference on the last line:

import time
import datetime

timenow = time.time()
timedifference = time.time() - timenow
timedifference = datetime.timedelta( seconds=timedifference )
print( "%s" % str(timedifference).split('.')[0] )

generates:

0:00:00

edited May 11 '20 at 00:22

answered May 11 '20 at 00:15

Marc Compere

290
4
17

got to admin it both elegant and simple (pythonic in my opinion) – Chris Dec 03 '21 at 18:38

Seb · Answer 2 · 2021-02-24T14:44:55.867

3

Another solution is to split the fractional part numerically and format it separately:

>>> seconds = 123.995
>>> isec, fsec = divmod(round(seconds*100), 100)
>>> "{}.{:02.0f}".format(timedelta(seconds=isec), fsec)
'0:02:04.00'

As you can see, this takes care of the rounding. It is also easy to adjust the output precision by changing 100 above to another power of 10 (and adjusting the format string):

def format_td(seconds, digits=2):
    isec, fsec = divmod(round(seconds*10**digits), 10**digits)
    return ("{}.{:0%d.0f}" % digits).format(timedelta(seconds=isec), fsec)

edited Feb 24 '21 at 14:44

answered Jan 17 '21 at 17:55

Seb

4,422
14
23

This is good but I still get something like 1:00:20.30, while I want for example 01:00:20.30. I tried to apply `{:0>8}.{:02.0f}` but it fails. Also `{%H:%M:%S}.{02.0f}` not working. Can I write it correctly in a quick way? – Peter.k Apr 18 '23 at 18:10
@Peter.k The `{:0>8}.{:02.0f}` approach should work as long as you wrap `timedelta(seconds=isec)` with `str(...)`. – Seb Apr 18 '23 at 18:31

score 2 · Accepted Answer · answered May 17 '19 at 19:31

You'll have to format it yourself. A timedelta object contains days, seconds and microseconds so you'll have to do the math to convert to days/hours/min/sec/microsec and then format using python string.format. For your microsec, you'll want ((microsec+5000)/10000) to get the top two digits (the +5000 is for rounding).

score 2 · Answer 4 · answered Oct 29 '21 at 15:34

2

A bit late, but here's a 2021 answer with f-strings (modified from @Seb's original answer):

def format_td(seconds, digits=3):
    isec, fsec = divmod(round(seconds*10**digits), 10**digits)
    return f'{timedelta(seconds=isec)}.{fsec:0{digits}.0f}'

answered Oct 29 '21 at 15:34

rv.kvetch

9,940
3
24
53

How can I format timedelta microseconds to 2 decimal digits?

4 Answers4