python while loop gets stuck

Question

Why the below code gets stuck after entering either int. or str in sublime text ? same code runs fine with python3 command line or pycharm.

print ('\n asks for an integer and prints the square of it\n')
def square(num):
    return num **2

def ask():
    while True:
        try:
            usr_input = int(input('Input an integer:'))
        except:
            print (f'An error occurred! Please try again!')
            continue
        else:
           return (f'Thank you, your number squared is:{square(usr_input)}')
print(ask())

You need to break your while True infinite loop for rhat which you are not doing now — Devesh Kumar Singh, May 20 '19 at 02:04
Ohh yes didn’t see that, but the OP is doing try except else which I am unsure is a valid way to use try catch. Perhaps he needs to use finally? — Devesh Kumar Singh, May 20 '19 at 02:08
Have you ran your code through a debugger or stepped through it at all? At what point is it actually getting stuck? — CTheCheese, May 20 '19 at 02:17
It should work tho. This is probably a bad advise/comment but how long are you using sublime? Or is it needed? An alternative would be using visual studio code. That comes close to sublime. — Tom-Oliver Heidel, May 20 '19 at 02:17
Check what version of Python comes with your version of Sublime Text. It may trail the current version of Python, and `f`-strings were new in in Python 3.6. — BoarGules, May 20 '19 at 04:18

Naveen Kumar · Answer 1 · 2019-05-20T03:36:58.363

-1

       return (f'Thank you, your number squared is:',square(usr_input))
print(ask())

You need to use square function like this. Hope it was helpful.

edited May 20 '19 at 03:36

answered May 20 '19 at 03:28

Naveen Kumar

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1
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score -1 · Answer 2 · answered May 20 '19 at 04:27

Here is your Code just do one thing separate the square(usr_input)) and remove the curly brases

 print ('\n asks for an integer and prints the square of it\n')
def square(num):
    return num ** 2

def ask():
    while True:
        try:
            usr_input = int(input('Input an integer:'))
        except:
            print ('An error occurred! Please try again!')
            continue
        else:
            return ('Thank you, your number squared is:',square(usr_input))

print(ask())

Output-

asks for an integer and prints the square of it

Input an integer:5
('Thank you, your number squared is:', 25)

python while loop gets stuck

2 Answers2