How does python evaluate this with both an 'and' and an 'or'?
lambda x: isinstance(x[1], Decimal) and (str(x[0]), str(x[1])) or (str(x[0]), x[1])
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joannarch
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Have you made *any* effort to solve this yourself? – Scott Hunter May 20 '19 at 18:24
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any resource only gives examples for two, not three at a time. – joannarch May 20 '19 at 18:25
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is it ((1 and 2) or 3) or (1 and (2 or 3))? – joannarch May 20 '19 at 18:26
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`and` has higher precedence than `or` so it will be the former – Endyd May 20 '19 at 18:28
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thank you for your help! – joannarch May 20 '19 at 18:29
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According to the documentation, the precedence for boolean operators is:
- NOT is evaluated before all
- AND is evaluated before OR
- OR
Link: Operator Precedence
Mikael
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