How to randomize two players to "X" and to "O?

Question

I'm making a tic tac toe game and I have randomily assign player 1 one to either "X" or "O" and same with player 2. I have no clue how to start the code

It should make player one either X or O and make player 2 whatever is left over from player 1

Answer 1

You can generate a random number between for example 0 and 1 by using a random object or the Math.Random() function.

Based on the random number you can select via if and else, which letter "X"/"O" the first player will get. The second player can then be assigned what is left.

Have look on Math.Random: Math.random() explanation

Answer 2

public class RandomTicTacToeSymbols {
    public static void main(String args[]) {
        String[] symbols = {"X" , "O"};

        int randomIndex = (int) Math.round( Math.random());
        String playerOneSymbol = symbols[randomIndex];
        String playerTwoSymbol = symbols[(randomIndex+1) % 2];

        System.out.println(String.format("Player 1 -> %s - Player 2 -> %s", playerOneSymbol, playerTwoSymbol) );
    }
}