char ch = 'A';ch += 32;. //This works finech = ch + 32; //this doesn't work
Why does line 2 work and line 3 doesn't, although they represent the same operation?
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I believe that in the second case, the RHS `ch + 32` is being treated as a completely integer expression. – Tim Biegeleisen May 22 '19 at 11:33
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1"doesnt work" - what does that mean? Please post the entire error code and the complete code to reproduce it ([mcve]). – Zabuzard May 22 '19 at 11:34
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Why don't you use Character class static methods?
https://docs.oracle.com/javase/7/docs/api/java/lang/Character.html
Character.toUpperCase(ch)
Nevertheless to answer your question, java requires you to cast primitives when you would loose precision during the assignment, so when on the righand site you have 32bit int and on the lefthand side 16bit you need to explicitly cast it. So when a righthand side is an int, you need to cast. If you cast to char your code will work fine. Still just use Character class
long l = 34; //this is fine
int i = 2L; //compile error, you loose precision in that assigment
Also check Why are we allowed to assign char to a int in java?
maslan
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