If the # of columns/line lengths are variable, it isn't possible to find the line you want without "reading" (ie, processing) every character of the file that comes before that, and counting the line terminators. And the fastest way to process them in python, is to use iteration.
As to the fastest way to do that with a large file, I do not know whether it is faster to iterate by line this way:
with open(file_name) as f:
for line,_ in zip(f, range(50)):
pass
lines = [line for line,_ in zip(f, range(10))]
...or to read a character at a time using seek
, and count new line characters. But it is certainly MUCH more convenient to do the first.
However if the file gets read a lot, iterating over the lines will be slow over time. If the file contents do not change, you could instead accomplish this by reading the whole thing once and building a dict
of the line lengths ahead of time:
from itertools import accumulate
with open(file_name) as f:
cum_lens = dict(enumerate(accumulate(len(line) for line in f), 1))
This would allow you to seek to any line number in the file without processing the whole thing ever again:
def seek_line(path, line_num, cum_lens):
with open(path) as f:
f.seek(cum_lens[line_num], 0)
return f.readline()
class LineX:
"""A file reading object that can quickly obtain any line number."""
def __init__(self, path, cum_lens):
self.cum_lens = cum_lens
self.path = path
def __getitem__(self, i):
return seek_line(self.path, i, self.cum_lens)
linex = LineX(file_name, cum_lens)
line50 = linex[50]
But at this point, you might be better off loading the file contents into some kind of database. It depends on what you're trying to do, and what kind of data the file contains.