I can not use sprintf, or any other function that puts everything together in a string n, I can not really use any libc function, it's part of a challenge I'm trying to solve
Given:
int x=5;
int y=2;
Expected Output:
res = 52;
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Krishna
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Yuri Albuquerque
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Do you want `y=52` leaving `x=5`? – Krishna May 25 '19 at 05:25
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I want x = 52, or another variable that has the concatenation of 2, without using any libc function – Yuri Albuquerque May 25 '19 at 05:27
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1Well this would print 52 leaving initial values of x, y intact `int result = (x<<3)+(x<<1)+y;` – Krishna May 25 '19 at 05:42
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Thanks a lot, I was thinking of doing bitwise myself, it helped me a lot, hehe, for higher values than 9, the result would not compensate to do this, but I'll get value from 1 to 9 even then, vlw, :) @Krishna – Yuri Albuquerque May 25 '19 at 05:59
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1I just found a similar answer which way more faster https://stackoverflow.com/a/12700533/8963175 – Abhishek May 25 '19 at 06:07
1 Answers
1
This is one posible solution:
#include <stdio.h>
int main()
{
int x= 342;
int y= 224;
int aux = y;
while( aux ) {
aux /= 10;
x*= 10;
}
x+= y;
printf("x= %d\r\n", x); // prints 342224
}
BlueStrat
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Many thanks, I tested here and with some values it really works, however if x is less than 10, it will do the sum – Yuri Albuquerque May 25 '19 at 05:39
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People, now I need to get all the numbers of the array, for example: char * array = "12345", I want to have int x = 12345, again without using the libc functions, I tried to adapt from the examples that passed me to solve, but without success , thankful. – Yuri Albuquerque May 25 '19 at 14:27
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The solution referred to by @Abhishek is much better, avoiding a division in the loop – BlueStrat May 25 '19 at 17:22