get dict every item and get a new list in one line

Question

I have a dict,like this:

{'brand': ['Three Squirrels', 'liang', 'BE'],
  'op': ['交', '差'],
  'cate': ['aaaa','bbbb','cccc']
}

Now, I want to make a new list,like this:

 [
 {'brand':'Three Squirrels','op':'交','cate':'aaaa'},
 {'brand':'Three Squirrels','op':'差','cate':'bbbb'},
 {'brand':'liang','op':'交','cate':'aaaa'},
 {'brand':'liang','op':'交','cate':'bbbb'},
 .....
 .....
]

list len is 3*2*3 = 18

How can I do this in one line code?

Answer 1

You can generate all possible values via itertools.product Then you can iterate through the values and create your list of dictionaries by zipping together keys and values

from itertools import product

dct = {'brand': ['Three Squirrels', 'liang', 'BE'],
  'op': ['交', '差'],
  'cate': ['aaaa','bbbb','cccc']
}

#Get the list of keys
keys = dct.keys()

#Iterate through the values, and zip key and value together
result = [ dict(zip(keys, item)) for item in product(*dct.values())]

print(result)
print(len(result))

The output will be

[{'brand': 'Three Squirrels', 'op': '交', 'cate': 'aaaa'}, 
{'brand': 'Three Squirrels', 'op': '交', 'cate': 'bbbb'}, 
{'brand': 'Three Squirrels', 'op': '交', 'cate': 'cccc'}, 
{'brand': 'Three Squirrels', 'op': '差', 'cate': 'aaaa'},
 {'brand': 'Three Squirrels', 'op': '差', 'cate': 'bbbb'}, 
{'brand': 'Three Squirrels', 'op': '差', 'cate': 'cccc'}, 
{'brand': 'liang', 'op': '交', 'cate': 'aaaa'}, 
{'brand': 'liang', 'op': '交', 'cate': 'bbbb'}, 
{'brand': 'liang', 'op': '交', 'cate': 'cccc'}, 
{'brand': 'liang', 'op': '差', 'cate': 'aaaa'}, 
{'brand': 'liang', 'op': '差', 'cate': 'bbbb'}, 
{'brand': 'liang', 'op': '差', 'cate': 'cccc'}, 
{'brand': 'BE', 'op': '交', 'cate': 'aaaa'}, 
{'brand': 'BE', 'op': '交', 'cate': 'bbbb'}, 
{'brand': 'BE', 'op': '交', 'cate': 'cccc'}, 
{'brand': 'BE', 'op': '差', 'cate': 'aaaa'}, 
{'brand': 'BE', 'op': '差', 'cate': 'bbbb'}, 
{'brand': 'BE', 'op': '差', 'cate': 'cccc'}]

18