Segmentation fault when passing array

Asked May 29 '19 at 05:30

Active May 29 '19 at 05:51

Viewed 37 times

The following simple c++ program always gives segmentation fault, which I cannot see the reason. This error goes away if I set N2=1000.

But I don't think the size of the lists is large at all. Commenting out evolve, I tried define 10 times larger arrays in the main function, which gives no error at all.

#include <iostream>

const int N1 = 481, N2 = 2000;

using std::cout; using std::endl;

void evolve(double* lista, double* listb){
    int ha = 10; ha++;
    cout << 88 << endl;
}

int main(int argc, char** argv){

    double list1[N1 * N2], list2[N1 * N2];
    evolve(list1, list2);
    cout << "End." << endl;
    return 0;
}

edited May 29 '19 at 05:51

asked May 29 '19 at 05:30

xiaohuamao

Probably a stack overflow. – Michael Chourdakis May 29 '19 at 05:36
@MichaelChourdakis But I can't see what might be too larger here. – xiaohuamao May 29 '19 at 05:45
481*2000*sizeof(double)*2 = 15392000 – Michael Chourdakis May 29 '19 at 05:47
memset(list1,0x00,N1*N2); memset(list2,0x00,N1*N2); – abbasi_ahsan May 29 '19 at 05:48
@MichaelChourdakis I tried defining 10 times larger arrays in the main function, which gives no error at all. Do I misunderstand something? – xiaohuamao May 29 '19 at 05:52
1

Arrays defined inside a function (including `main`) are allocated on the stack, which is of limited size. Arrays defined at global scope are not, and are effectively of unlimited size in 64 bit programs. – Paul Sanders May 29 '19 at 07:01

Segmentation fault when passing array

0 Answers0