This problem has two parts, first we need to identify any characters in the string which we don't want. From your use case it seems that anything that is not numeric needs to go. This is simple enough as the standard library defines a function std::isdigit (simply add the following inclusion "#include <locale>
") which takes a character and returns a bool which indicates whether or not the character is numeric.
Second we need a way to quickly and cleanly remove all occurrences of these from the string. Thus we can use the 'Erase Remove' idiom to iterate through the string and do what we want.
string s = "123'4'5";
s.erase(std::remove_if(s.begin(), s.end(), [](char x)->bool {return !std::isdigit(x);}), s.end());
In the snippit above we're calling erase on the string which takes two iterators, the first refers to where we want to begin to delete from and the second tells the call where we want to delete to. The magic in this trick is actually all in the call to remove_if (include "#include <algorithm>
" for it). remove_if actually works by shifting the elements (or characters) of string forward to the end of the string.
So "123'4'5'" becomes "12345'''", then it returns an iterator to where it shifted these characters to which is then passed to erase to tell it remove the characters starting here. In the end we're left with "12345" as expected.
Edit: Forgot to mention, remove_if also takes a predicate here I'm using a lambda which takes a character and returns a bool.