JavaScript: Add space between Char and Number with Regex

Question

Hello I have a plate number BZ8345LK and want convert to BZ 8345 LK (adding space between char and number).

I tried with this Regex but not working, only space first char with number. Ex BZ 8345LK, the 'LK' keep not space with number.

var str = 'BZ8345LK';
str.replace(/[^0-9](?=[0-9])/g, '$& ');
# return BZ 8345LK, I want BZ 8345 LK

here is explained why https://stackoverflow.com/questions/1144783/how-to-replace-all-occurrences-of-a-string-in-javascript — GrafiCode, May 31 '19 at 09:34

Code Maniac · Accepted Answer · 2019-08-31T05:43:26.330

6

You can use this regex

[a-z](?=\d)|\d(?=[a-z])

let str = 'BZ8345LK'

let op = str.replace(/[a-z](?=\d)|\d(?=[a-z])/gi, '$& ')

console.log(op)

edited Aug 31 '19 at 05:43

answered May 31 '19 at 09:34

Code Maniac

This best choice in dynamic text input like on change. – Puyup May 31 '19 at 09:39
Can you force remove extra space in number `BZ 83 45 LK` to `BZ 8345 LK` – Puyup May 31 '19 at 09:43
If number format `BZ83 45LK`, how to keep output `BZ 8345 LK` – Puyup May 31 '19 at 11:01
1

@Puyup First [strip out the spaces](https://stackoverflow.com/a/10800402/5527985) then use the answer. – bobble bubble May 31 '19 at 11:22
@Puyup you can simply remove all the space `str.replace(/\s+/g,'')` – Code Maniac May 31 '19 at 12:24

score 2 · Answer 2 · answered May 31 '19 at 09:33

2

You should alternate with the other possibility, that a number is followed by a non-number:

var str = 'BZ8345LK';
console.log(str.replace(/[^0-9](?=[0-9])|[0-9](?=[^0-9])/g, '$& '));

answered May 31 '19 at 09:33

If used in text input with onChange this code add more extra space each char and number. – Puyup May 31 '19 at 09:40

score 0 · Answer 3 · answered May 31 '19 at 09:41

0

An anoher option is to use:

^[^\d]+|[\d]{4}

Search for any not numeric character [^\d] followed by 4 numeric [\d]{4} characters

const str = 'BZ8345LK'
let answer = str.replace(/^[^\d]+|[\d]{4}/gi, '$& ')
console.log(answer)

answered May 31 '19 at 09:41

nanndoj

score 0 · Answer 4 · answered May 31 '19 at 10:10

0

Try with this

var str = "BZ8345LK";
var result = str.replace(/([A-Z]+)(\d+)([A-Z]+)/, "$1 $2 $3");
console.log(result);

answered May 31 '19 at 10:10

Yves Kipondo

4 Answers4