How to get day month and year in integer from given string date in pattern dd-MMM-yyyy

Question

I have a string date in format (dd-MMM-yyyy) like (23-SEP-2019). I want to seperate day month and year from above string in integer like day = 23, month = 09, year = 2019.

Qingfei Yuan · Accepted Answer · 2019-05-31T16:06:48.277

0

String pattern = "dd-MMM-yyyy";
SimpleDateFormat simpleDateFormat = new SimpleDateFormat(pattern);
Date date = simpelDateFormat.parse(yourdateString);
Calendar now = Calendar.getInstance();
now.setTime(date);
int year = now.get(Calendar.YEAR);
int month = now.get(Calendar.MONTH) + 1; // Note: zero based!
int day = now.get(Calendar.DAY_OF_MONTH);

edited May 31 '19 at 16:06

answered May 31 '19 at 15:11

Qingfei Yuan

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but date.getYear is a deprecated method in android – Dheeraj Pandey May 31 '19 at 15:17
You can use Calendar class or 3-rd party library. – Qingfei Yuan May 31 '19 at 15:21
I would not recommend importing extra libraries for something this simple. Not only is it hassle, but you will probably be importing much more than you actually need with far less knowledge of what could go wrong. – CasualViking May 31 '19 at 15:39
modified with Calendar – Qingfei Yuan May 31 '19 at 15:43
Thanks @yuan qingfei – Dheeraj Pandey May 31 '19 at 16:04
it worked for me – Dheeraj Pandey May 31 '19 at 16:05

score 0 · Answer 2 · answered May 31 '19 at 15:30

There's a few ways to do this, but I would go with this:

//convert it to a char array.
char[] asChars = dateString.toCharArray();
//Parse the date and year and from new strings.
int dayVal = Interger.ParseInt(""+asChars[0]+asChars[1]);
int yearVal = Interger.ParseInt(""+asChars[7]+asChars[8]+asChars[9]+asChars[10]);
//use a switch for the month.
int monthVal = 0;
String monthString = ""+asChars[3]+asChars[5]+asChars[6];
switch (monthString) {
    case "JAN" :
        monthVal = 1;
        break;
    case "FEB" :
        monthVal = 2;
        break;
    case "MAR"  :
        monthVal = 3;
        break;
    case "APR" :
        monthVal = 4;
        break;
    case "MAY" :
        monthVal = 5;
        break;
    case "JUN" :
        monthVal = 6;
        break;
    case "JUL" :
        monthVal = 7;
        break;
    case "AUG" :
        monthVal = 8;
        break;
    case "SEP" :
        monthVal = 9;
        break;
    case "OCT" :
        monthVal = 10;
        break;
    case "NOV" :
        monthVal = 11;
        break;
    case "DEC" :
        monthVal = 12;
        break;
}

You'll need to put that in a try block and you'll want a catch for NumberFormatException and IndexOutOfBounds, in both cases the string was formatted incorrectly.

You will also separately need to check that the month string matched a month, so either add a default case to the switch or have a check that monthVal>0 after all that.

If you really want to be sure the original string was formatted correctly (which is a separate issue but I think still relevant) then you could check the string is of length 11 before all of that.

I don't see much room for shortening it without just using a different approach. Why is the length of the code a problem for you? — CasualViking, May 31 '19 at 18:34

score 0 · Answer 3 · answered May 31 '19 at 15:33

You can use java 8 LocalDate feature. I provide below the code, you can check.

String dateStr = "23-Sep-2019";
    DateTimeFormatter formatter_1 = DateTimeFormatter.ofPattern("dd-MMM-yyyy");
    LocalDate localDate = LocalDate.parse(dateStr, formatter_1);
    System.out.println("localDate_1 = " + localDate);
    int day = localDate.getDayOfMonth();
    int month = localDate.getMonthValue();
    int year = localDate.getYear();
    System.out.println(day + "-" + month + "-" + year);

How to get day month and year in integer from given string date in pattern dd-MMM-yyyy

3 Answers3