Missing last line in file

Question

Using the code below. It will not copy the last line in the file.

I have tried the following means of reading the file.

"while IFS=$'\n' read -d '' -r -a myLine" or "while IFS=$'\n' read -r -a myLine"

while read -a myLine
do
  for ((i=0;i<"${#myLine[@]}";i++))
  do
    temp_array[$i]+=" ${myLine[$i]}"
  done
done < $1

File contains numbers like:

1 2
3 4
5 6

when echo is used to see what is in the array i get

1 2
3 4

this is where it drops off the last line.

@melpomene no there is no termination of /n. the files vary and the code needs to account for with or without newline. — Dan, Jun 01 '19 at 21:40
A file without a newline by definition is not a POSIX text file and so YMMV trying to run POSIX tools that read text files on it. — Ed Morton, Jun 02 '19 at 02:11

score 1 · Answer 1 · answered Jun 01 '19 at 21:45

1

Since Bash 4:

mapfile -t MyArray < "$1"

answered Jun 01 '19 at 21:45

vintnes

2,014
7
16

score 1 · Answer 2 · answered Jun 02 '19 at 01:30

The problem is that on the last line, read hits the end of file rather an an end-of-line delimiter (newline character), so it returns a failure status and the loop exits. But it does put the content it read into the array variable, so check for that to make it process that last line:

while read -a myLine || [[ ${#myLine[@]} -gt 0 ]]
do

This is very similar to the solution for read without -a; the only difference is how to test for a nonempty line after the last linefeed.

Missing last line in file

2 Answers2