Can't override 'sys.excepthook'

Question

I am trying to override sys.excepthook exception handling. However, it simply not works.

This is the code I am running.

from sys import excepthook

excepthook = lambda type, exception, traceback : print('foo')

raise Exception('bar')

The following code calls my overriden method:

from sys import excepthook

excepthook = lambda type, exception, traceback : print('foo')

try:
    raise Exception('bar')
except Exception as e:
    excepthook(Exception, e, e._traceback_)

This code is useless due to the fact sys.excepthook should catch unhandled exceptions.

I`m aware many people is having issues such as mine, however, none of the issues helped me solve my problem.

why-doesnt-sys-excepthook-work

adding-function-to-sys-excepthook

sys-excepthook-vs-handled-exceptions

Thanks.

score 1 · Answer 1 · answered Jun 04 '19 at 12:20

1

Got it.

The problem is in importing sysmodule.

import sys

sys.excepthook = lambda type, exception, traceback : print('foo')

And not this:

from sys import excepthook

It seems python does not know about excepthook function from sysso it declares a new variable called excepthook. That`s why it does not work as stated in docs.

answered Jun 04 '19 at 12:20

Vikto

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This has nothing to do with `excepthook` and everything with how names work in Python. – L3viathan Jun 04 '19 at 12:36
@L3viathan Yes. That`s what this answer says. Thanks. – Vikto Jun 04 '19 at 13:23

Can't override 'sys.excepthook'

1 Answers1