obtain the index of elements in a list that satisfy a condition

Question

I am trying to index the positions of a list of integers to obtain the position of the intergers that are >0.

This is my list:

paying=[0,0,0,1,0,3,4,0,5]

And this is the desired output:

[3,5,6,8]

rdo=paying[paying>0]

and tried:

rdo=paying.index(paying>0)

The output is in both cases

typeerror > not suported between instances of list and int

Answer 1

Use list comprehensions and enumerate built-in function:

paying=[0,0,0,1,0,3,4,0,5]
print([i for i, e in enumerate(paying) if e > 0])

[3, 5, 6, 8]

Answer 2

You can use list comprehension.

paying=[0,0,0,1,0,3,4,0,5]
result = [index for index, value in enumerate(paying) if value > 0]

Answer 3

Use enumerate:

paying=[0,0,0,1,0,3,4,0,5]
[i for i, e in enumerate(paying) if e > 0]

OR

[paying.index(e) for e in paying if e > 0]

Result:  [3, 5, 6, 8]