issues creating a list of integers with its start and stop point

Question

I would like to create a list from 0 to 11 with starting point 6 and that runs all the range of numbers to obtain the following output:

[6,7,8,9,10,11,0,1,2,3,4,5]

I would like to know if there was an array creation routine to do so: Something like:

range(start=7,stop=6,step=1)

Do you want a list, or a numpy array? They're not the same data type, so the best technique to make one may not be the best way to make the other. — Blckknght, Jun 08 '19 at 06:19
Given `range(start=7,stop=6,step=1)` how is it even obvious that the start is 0 and end is 11? — cs95, Jun 08 '19 at 06:20
You can do rotation as described here https://stackoverflow.com/questions/9457832/python-list-rotation — Abhishek Dujari, Jun 08 '19 at 06:21
Perhaps you want something like `start, end, mid = 0, 11, 6; [*range(mid, end+1), *range(start, mid)]` but without further clarification or examples, don't think much more can be said — cs95, Jun 08 '19 at 06:23

score 2 · Answer 1 · answered Jun 08 '19 at 06:21

2

Does this fulfill your needs?

import numpy as np

ar = np.arange(12)
ar = np.roll(ar, 6)

# or np.roll(np.arange(12), 6)

print(ar)

Returns:

array([ 6,  7,  8,  9, 10, 11,  0,  1,  2,  3,  4,  5])

answered Jun 08 '19 at 06:21

Anton vBR

score 2 · Accepted Answer · answered Jun 08 '19 at 06:26

2

Simple way to generate list would be like:

a = list(range(6, 12))+list(range(0, 6))
print(a)

answered Jun 08 '19 at 06:26

xanjay

score 1 · Answer 3 · answered Jun 08 '19 at 06:27

1

If you just want an ordinary Python list, you can form it from two ascending lists like so:

>>> list(range(6, 12)) + list(range(6))
[6, 7, 8, 9, 10, 11, 0, 1, 2, 3, 4, 5]
>>>

answered Jun 08 '19 at 06:27

Tom Karzes

3 Answers3